맥그로힐 회로이론 4판 솔루션 McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th 풀이
맥그로힐 회로이론 4판 솔루션 McGRAW HILL 4th
Fundamentals of Electric Circuits McGRAW HILL 4th 풀이
맥그로힐 회로이론 4판 솔루션 McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th
1장부터 10장까지 다 있습니다.
practice problem
problem
Problem Solving WorkbookChapter 1, Problem 1
How many coulombs are represented by these amounts of electrons:
(a) (b) 1710482.6×181024.1×
(c) (d) 191046.2×2010628.1×
Chapter 1, Solution 1
(a) q = 6.482x1017 x [-1.602x10-19 C] = -0.10384 C
(b) q = 1. 24x1018 x [-1.602x10-19 C] = -0.19865 C
(c) q = 2.46x1019 x [-1.602x10-19 C] = -3.941 C
(d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C
Chapter 1, Problem 2.
Determine the current flowing through an element if the charge flow is given by
(a) ()()mC 83+=ttq
(b) ()C 2)482t-t(tq+=
(c) ()()nC e5e3tqt2-t−−=
(d) ()pCt sin10 120tqπ=
(e) ()Ct 50cos204μtetq−=
Chapter 1, Solution 2
(a) i = dq/dt = 3 mA
(b) i = dq/dt = (16t + 4) A
(c) i = dq/dt = (-3e-t + 10e-2t) nA
(d) i=dq/dt = 1200120ππcost pA
(e) i =dq/dt = −+−ettt48050100050(cossin) Aμ
PROPRIETARY MATERIAL. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. No part
of this Manual may be displayed, reproduced or distributed in any form or by any
자료출처 : http://www.ALLReport.co.kr/search/Detail.asp?pk=14031203&sid=knp868group1&key=
[문서정보]
문서분량 : 900 Page
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자료제목 : 맥그로힐 회로이론 4판 솔루션 McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th
파일이름 : [솔루션] 회로이론 McGRAW-HILL 4판 Fundamentals of Electric Circuits McGRAW-HILL 4th.zip
키워드 : 맥그로힐,회로이론,4판,솔루션,McGRAW,HILL,4th,Fundamentals,of,Electric
자료No(pk) : 14031203
맥그로힐 회로이론 4판 솔루션 McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th
1장부터 10장까지 다 있습니다.
practice problem
problem
Problem Solving WorkbookChapter 1, Problem 1
How many coulombs are represented by these amounts of electrons:
(a) (b) 1710482.6×181024.1×
(c) (d) 191046.2×2010628.1×
Chapter 1, Solution 1
(a) q = 6.482x1017 x [-1.602x10-19 C] = -0.10384 C
(b) q = 1. 24x1018 x [-1.602x10-19 C] = -0.19865 C
(c) q = 2.46x1019 x [-1.602x10-19 C] = -3.941 C
(d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C
Chapter 1, Problem 2.
Determine the current flowing through an element if the charge flow is given by
(a) ()()mC 83+=ttq
(b) ()C 2)482t-t(tq+=
(c) ()()nC e5e3tqt2-t−−=
(d) ()pCt sin10 120tqπ=
(e) ()Ct 50cos204μtetq−=
Chapter 1, Solution 2
(a) i = dq/dt = 3 mA
(b) i = dq/dt = (16t + 4) A
(c) i = dq/dt = (-3e-t + 10e-2t) nA
(d) i=dq/dt = 1200120ππcost pA
(e) i =dq/dt = −+−ettt48050100050(cossin) Aμ
PROPRIETARY MATERIAL. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. No part
of this Manual may be displayed, reproduced or distributed in any form or by any
자료출처 : http://www.ALLReport.co.kr/search/Detail.asp?pk=14031203&sid=knp868group1&key=
[문서정보]
문서분량 : 900 Page
파일종류 : ZIP 파일
자료제목 : 맥그로힐 회로이론 4판 솔루션 McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th
파일이름 : [솔루션] 회로이론 McGRAW-HILL 4판 Fundamentals of Electric Circuits McGRAW-HILL 4th.zip
키워드 : 맥그로힐,회로이론,4판,솔루션,McGRAW,HILL,4th,Fundamentals,of,Electric
자료No(pk) : 14031203
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